M22 #3.5: lix number codes (pt 2)
Imagine constructing a simple rectangular shed with a gabled ceiling using, as dimensions,
the square roots of 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, and 15, each multiplied by 7.68, (28 x .03).
Imagine, next to your shed, building a simple rectangular workshop with a flat ceiling using,
as dimensions, the square roots of ( 213 x .009 ) x 4, 21, 9, 25, 16, 20, and 5.
Imagine designing these structures from scratch.
If you've arrived here from a direct link, unfamiliar with lix measure and its' application to the Hi Phive, (Kings')
chamber you don't have to go here first but it will help you better understand the following presentation.
phive and point phive
5.5 x .5 = 1.1180339887 = 1.25.5
5.5 x .5 + .5 = 1.6180339887 = phi
Four codes were discovered in the Kings' chamber dimensions in the early 1980's
by Joseph Edward Batter after we completed the "Machine Array", the Great Pyramid cross section.
Following his death, in '94, i collated some of the basic elements of our collaboration, including the Codes,
and opened a webpage,"the lix unit" in late '96, followed by "lixcaliber" in 1998.
In mid January this year, while re-working the lix number code, i suddenly realized
the squared dimensions shared another common factor: [G] = (213 x .009),
(the sum of the 7 squared dimensions of the Hi Phive chamber divided by 100.)
Looking back it now seems so obvious; in fact the answer was there for all to see, ever since Joe
first deciphered the codes and throughout the 12 years they've been posted on the web. My deep chagrin at
having found 73.728 without realizing what it meant 5 years ago will hopefully fade in time.
With [G] resolved i thought it likely the module would apply to other areas of the Pyramid and went to
the Google to find Queens Chamber dimensions. I knew the width was the same as the Kings, (from the
Machine Array cross section) but had no idea what the other dimensions were. On Tim Hunklers site i was
delighted to find William K. Simpson had already deduced part of the Kings chamber sequence using a
unit dimension of 103.03 primitive inches. More exciting was his discovery of a portion of the Queens chamber
sequence using a unit dimension of 92.175077 + primitive inches and the square roots of 4,5,6,7,9,10,11 and 15.
As you will see, if Simpson had employed a unit dimension of 92.16 p.i. = 9.62 = (25x .3)2, the chambers
of the Great Pyramid would have become instantly transparent.
06 15 '08
( If you quickly scan this presentation, jumping over numbers and formulas in a 20th Century rush to get
to the, "and so?", the punch line, you will miss the point and it is far too good a point to miss. The numbers and
formulas generating these dimensions are the message, but don't take my word, nor anyone else's. Confirm them
yourself by reading each step and doing the simple arithmetic as you go. It won't take long and by the end of
this brief, if nothing else, you will have a deeper appreciation for the art of shed building.)
02 20 '08
No Queen was ever interred in the "Queens" Chamber. As with the Hi Phive chamber the name
should reflect the purpose behind the design and is hereafter referred to as the "Point Phive" chamber.
William Kelly Simpson deduced numerical relationships in the "Point Phive" chamber
using a "Unit Dimension", (a module), of 92.173077+ "pyrimitive" inches. Simpson discovered the:
wall height = UD x 2 , width = UD x 5.5, length = UD x 6.5, height apex = UD x 7.5
diag end wall = UD x 3, diag floor = UD x 10.5, diag side wall = UD x 11.5, cubic diag = UD x 15.5
(note: floor diagonal and side wall diag are switched; corrected below )
squaring the factors produces the series: 4, 5, 6, 7, 9, 10, 11, 15 + = 67
Convert Simpsons "unit dimension" to feet: ( 92.173077 / 12 ) = 7.68108975.
Both the lix Number code and the fact the width of the Point Phive and
Hi Phive chambers are equal: 17.17300207 lix, suggest the unit dimension is exactly
7.68 lix: = ( 28 x .03 )
chamber width = 7.68 x 5.5 = 17.17300207 = [Y], [Y]2 = 294.912 lix
7.682 x 10 = 589.824 = diagonal side wall squared = [Y]2 x 2
7.68, Point Phive, [G] and Hi Phive
[G] = 73.728 = (213 x .009)
| Point
Phive line |
formula lix dimension = N | N2 | N2/ [G] = | N2 x 5 | = n x [Y2] | =
4n[G] = Hi Phive |
| height wall | 7.68 x 4 .5 = 15.36 | 235.9296 |
3.2 |
1179.648
|
4
|
16[G]
= [U2] |
| width |
7.68 x 5 .5 = 17.17300207 | 294.912 |
4 |
1474.56 |
5 | 20[G] = [T2] |
| length |
7.68
x 6 .5 = 18.81208122 |
353.8944 |
4.8 |
1769.472 |
6 | 24[G] = [T2]
+
[Y2]
|
| height
apex |
7.68
x 7 .5 = 20.31937007 |
412.8768 |
5.6 |
2064.384 |
7 | 28[G]
= [T2]
+
2[Y2] |
| (?) |
7.68 x 8 .5 = 21.72232032 |
471.8592 |
6.4 |
2359.296 |
8 |
32[G]
= 2[U2] |
| diag end wall | 7.68 x 9 .5 = 23.04 | 530.8416 |
7.2 |
2654.208 |
9 |
36[G] = [T2] + [U2] |
| diag
side wall |
7.68 x 10 .5 = 24.28629243 | 589.824 |
8 |
2949.12 |
10 | 40[G]
=
2[T2] |
| diag
floor |
7.68
x 11 .5 = 25.47167839 |
648.8064 |
8.8
|
3244.032 |
11 | 44[G]
= 2[T2]
+
[Y2] |
| cubic
diag |
7.68
x 15 .5
= 29.74451209 |
884.736 |
12 |
4423.68 |
15 |
60[G]
= 3[T2] |
| totals |
= 195.92925659 | 4423.68 | 60 |
22118.4 |
75 |
300[G] = 15[T2] |
phive and the power of point phive03 13 '08
( n[G] / 5 ).5
eg) Hi Phive length = 34.34600414 lix = [U]
[U2] = 1179.648 = 16[G]
( 16[G] / 5 ).5 = 15.36 lix = Point Phive wall height
or) ( 4[Y2] / 5 ).5 = 15.36 lix
15.362 x 5 = [U2]
is missing at least one dimension: 8, while 15 is out of position.
Starting at the top of the far right column each dimension increases by 4[G]
with a gap of 8[G] between the height apex, 28[G] and the diagonal end wall, 36[G].
Extrapolating backwards: ( 32[G] / 5 ) .5 = 21.72232032 lix = ( 7.68 x 8 .5)
21.72232032 x 2.5.5 = 34.34600414 = [U] ( Hi Phive chamber length )
The sequence now resolves itself, unfolding as 4 pairs, each total 15, around the cubic diagonal:
4, 5, 6, 7, 15, 8, 9, 10, 11,
4 + 11, 5 + 10, 6 + 9, 7 + 8, = 60, + 15 = 75
In the Hi Phive chamber the [G] lix code, where this started back in mid January,
also unfolds as pairs, each total 25, around the cubic diagonal:
4, 21, 9, 25, 16, 20, 5 + = 100
03 14 '08
13
Simpsons' code neglects the most obvious triangle in the room,
at half the width of the chamber, down the centre, from the ceiling apex to the opposite floor.
Triangle: floor length, 7.68 x 6.5, apex height, 7.68 x 7.5, diagonal, 7.68 x 13.5
The location of 12.5 and 8.5 is unknown at present however 8.5 fits somewhere:
( 7.68 x 8 .5) = 21.272232032, x 2.5.5 = 34.34600414 = [U] Hi Phive length
12.5, at twice the length, has its' own story to tell. 73.728 / 7.68 = 9.6
9.63 = 884.736 (cubic diagonal squared)
| Point Phive
line |
formula = lix dimension |
N2 |
N2/ [G] | N2
x 5 |
=
n
x [Y2] |
=
4n[G]
|
| ? |
7.68 x 12.5
= 26.60430040 |
707.7888 ( 19.23 /10 ) |
9.6 |
3538.944 |
12 |
48[G]
|
| Diag
Apex |
7.68 x 13.5
= 27.69063379 |
766.7712 |
10.4 |
3833.856 |
13 |
52[G] |
| totals |
54.29493419 |
1474.56
= [T2] |
20 |
7372.8 |
25 |
100[G] |